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前面学习了 set 集合,本节来一一学习 set 类型提供的方法。首先,通过 dir(set) 命令可以查看它有哪些方法:

>>> dir(set)
['add', 'clear', 'copy', 'difference', 'difference_update', 'discard', 'intersection', 
'intersection_update', 'isdisjoint', 'issubset', 'issuperset', 'pop', 'remove', 
'symmetric_difference', 'symmetric_difference_update', 'union', 'update']


各个方法的具体语法结构及功能如表 1 所示。

表 1 Python set方法
方法名语法格式功能实例
add()set1.add()向 set1 集合中添加数字、字符串、元组或者布尔类型>>> set1 = {1,2,3}
>>> set1.add((1,2))
>>> set1
{(1, 2), 1, 2, 3}
clear()set1.clear()清空 set1 集合中所有元素>>> set1 = {1,2,3}
>>> set1.clear()
>>> set1
set()

set()才表示空集合,{}表示的是空字典
copy()set2 = set1.copy()拷贝 set1 集合给 set2>>> set1 = {1,2,3}
>>> set2 = set1.copy()
>>> set1.add(4)
>>> set1
{1, 2, 3, 4}
>>> set1
{1, 2, 3}
difference() set3 = set1.difference(set2)将 set1 中有而 set2 没有的元素给 set3>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set3 = set1.difference(set2)
>>> set3
{1, 2}
difference_update()set1.difference_update(set2)从 set1 中删除与 set2 相同的元素>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set1.difference_update(set2)
>>> set1
{1, 2}
discard()set1.discard(elem)删除 set1 中的 elem 元素>>> set1 = {1,2,3}
>>> set1.discard(2)
>>> set1
{1, 3}
>>> set1.discard(4)
{1, 3}
intersection()set3 = set1.intersection(set2)取 set1 和 set2 的交集给 set3>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set3 = set1.intersection(set2)
>>> set3
{3}
intersection_update()set1.intersection_update(set2)取 set1和 set2 的交集,并更新给 set1>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set1.intersection_update(set2)
>>> set1
{3}
isdisjoint()set1.isdisjoint(set2)判断 set1 和 set2 是否没有交集,有交集返回 False;没有交集返回 True>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set1.isdisjoint(set2)
False
issubset()set1.issubset(set2)判断 set1 是否是 set2 的子集>>> set1 = {1,2,3}
>>> set2 = {1,2}
>>> set1.issubset(set2)
False
issuperset()set1.issuperset(set2)判断 set2 是否是 set1 的子集>>> set1 = {1,2,3}
>>> set2 = {1,2}
>>> set1.issuperset(set2)
True
pop()a = set1.pop()取 set1 中一个元素,并赋值给 a>>> set1 = {1,2,3}
>>> a = set1.pop()
>>> set1
{2,3}
>>> a
1
remove()set1.remove(elem)移除 set1 中的 elem 元素>>> set1 = {1,2,3}
>>> set1.remove(2)
>>> set1
{1, 3}
>>> set1.remove(4)
Traceback (most recent call last):
  File "<pyshell#90>", line 1, in <module>
    set1.remove(4)
KeyError: 4
symmetric_difference()set3 = set1.symmetric_difference(set2)取 set1 和 set2 中互不相同的元素,给 set3>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set3 = set1.symmetric_difference(set2)
>>> set3
{1, 2, 4}
symmetric_difference_update()set1.symmetric_difference_update(set2)取 set1 和 set2 中互不相同的元素,并更新给 set1>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set1.symmetric_difference_update(set2)
>>> set1
{1, 2, 4}
union()set3 = set1.union(set2)取 set1 和 set2 的并集,赋给 set3>>> set1 = {1,2,3}
>>> set2 = {3,4}
>>> set3=set1.union(set2)
>>> set3
{1, 2, 3, 4}
update()set1.update(elem)添加列表或集合中的元素到 set1>>> set1 = {1,2,3}
>>> set1.update([3,4])
>>> set1
{1,2,3,4}